注意: 最新版のドキュメントをご覧ください。この第1版ドキュメントは古くなっており、最新情報が反映されていません。リンク先のドキュメントが現在の Rust の最新のドキュメントです。
Like C, all stack variables in Rust are uninitialized until a value is explicitly assigned to them. Unlike C, Rust statically prevents you from ever reading them until you do:
fn main() { let x: i32; println!("{}", x); }fn main() { let x: i32; println!("{}", x); }
src/main.rs:3:20: 3:21 error: use of possibly uninitialized variable: `x`
src/main.rs:3 println!("{}", x);
^
This is based off of a basic branch analysis: every branch must assign a value
to x before it is first used. Interestingly, Rust doesn't require the variable
to be mutable to perform a delayed initialization if every branch assigns
exactly once. However the analysis does not take advantage of constant analysis
or anything like that. So this compiles:
fn main() { let x: i32; if true { x = 1; } else { x = 2; } println!("{}", x); }
but this doesn't:
fn main() { let x: i32; if true { x = 1; } println!("{}", x); }fn main() { let x: i32; if true { x = 1; } println!("{}", x); }
src/main.rs:6:17: 6:18 error: use of possibly uninitialized variable: `x`
src/main.rs:6 println!("{}", x);
while this does:
fn main() { let x: i32; if true { x = 1; println!("{}", x); } // Don't care that there are branches where it's not initialized // since we don't use the value in those branches }fn main() { let x: i32; if true { x = 1; println!("{}", x); } // Don't care that there are branches where it's not initialized // since we don't use the value in those branches }
Of course, while the analysis doesn't consider actual values, it does have a relatively sophisticated understanding of dependencies and control flow. For instance, this works:
fn main() { let x: i32; loop { // Rust doesn't understand that this branch will be taken unconditionally, // because it relies on actual values. if true { // But it does understand that it will only be taken once because // we unconditionally break out of it. Therefore `x` doesn't // need to be marked as mutable. x = 0; break; } } // It also knows that it's impossible to get here without reaching the break. // And therefore that `x` must be initialized here! println!("{}", x); }let x: i32; loop { // Rust doesn't understand that this branch will be taken unconditionally, // because it relies on actual values. if true { // But it does understand that it will only be taken once because // we unconditionally break out of it. Therefore `x` doesn't // need to be marked as mutable. x = 0; break; } } // It also knows that it's impossible to get here without reaching the break. // And therefore that `x` must be initialized here! println!("{}", x);
If a value is moved out of a variable, that variable becomes logically uninitialized if the type of the value isn't Copy. That is:
fn main() { let x = 0; let y = Box::new(0); let z1 = x; // x is still valid because i32 is Copy let z2 = y; // y is now logically uninitialized because Box isn't Copy }fn main() { let x = 0; let y = Box::new(0); let z1 = x; // x is still valid because i32 is Copy let z2 = y; // y is now logically uninitialized because Box isn't Copy }
However reassigning y in this example would require y to be marked as
mutable, as a Safe Rust program could observe that the value of y changed:
fn main() { let mut y = Box::new(0); let z = y; // y is now logically uninitialized because Box isn't Copy y = Box::new(1); // reinitialize y }
Otherwise it's like y is a brand new variable.